(4-(1/t))-(3/t^2)=0

Solution for (4-(1/t))-(3/t^2)=0 equation:

D( t )

t^2 = 0

t = 0

t^2 = 0

t^2 = 0

1*t^2 = 0 // : 1

t^2 = 0

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

4-(1/t)-(3/(t^2)) = 0

4-t^-1-3*t^-2 = 0

t_1 = t^-1

4-3*t_1^2-1*t_1^1 = 0

4-3*t_1^2-t_1 = 0

DELTA = (-1)^2-(-3*4*4)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)+1)/(-3*2) or t_1 = (1-49^(1/2))/(-3*2)

t_1 = -4/3 or t_1 = 1

t_1 = -4/3

t^-1+4/3 = 0

1*t^-1 = -4/3 // : 1

t^-1 = -4/3

-1 < 0

1/(t^1) = -4/3 // * t^1

1 = -4/3*t^1 // : -4/3

-3/4 = t^1

t = -3/4

t_1 = 1

t^-1-1 = 0

1*t^-1 = 1 // : 1

t^-1 = 1

-1 < 0

1/(t^1) = 1 // * t^1

1 = 1*t^1 // : 1

1 = t^1

t = 1

t in { -3/4, 1 }